Base | Representation |
---|---|
bin | 1011010111101111011111… |
… | …1010000001000111011111 |
3 | 1122021020011200211220001012 |
4 | 2311323313322001013133 |
5 | 3114320122041401024 |
6 | 42331324201205435 |
7 | 2430163644441650 |
oct | 265736772010737 |
9 | 48236150756035 |
10 | 12502514012639 |
11 | 3a903172471a2 |
12 | 149b0a279087b |
13 | 6c8c9c634bb1 |
14 | 3131a6a5d527 |
15 | 16a3445eb50e |
hex | b5ef7e811df |
12502514012639 has 8 divisors (see below), whose sum is σ = 14288888060928. Its totient is φ = 10716215118840.
The previous prime is 12502514012609. The next prime is 12502514012693. The reversal of 12502514012639 is 93621041520521.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a de Polignac number, because none of the positive numbers 2k-12502514012639 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12502514012596 and 12502514012605.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12502514012609) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18431687 + ... + 19097960.
It is an arithmetic number, because the mean of its divisors is an integer number (1786111007616).
Almost surely, 212502514012639 is an apocalyptic number.
12502514012639 is a deficient number, since it is larger than the sum of its proper divisors (1786374048289).
12502514012639 is an equidigital number, since it uses as much as digits as its factorization.
12502514012639 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37577245.
The product of its (nonzero) digits is 129600, while the sum is 41.
The spelling of 12502514012639 in words is "twelve trillion, five hundred two billion, five hundred fourteen million, twelve thousand, six hundred thirty-nine".
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