Search a number
-
+
12503155117 = 25149813367
BaseRepresentation
bin10111010010011111…
…10000000110101101
31012021100220002102011
423221033300012231
5201101301430432
65424402001221
7621561031165
oct135117600655
935240802364
1012503155117
115336783552
12250b346211
131243482a4b
148687955a5
154d2a0d847
hex2e93f01ad

12503155117 has 4 divisors (see below), whose sum is σ = 12552968736. Its totient is φ = 12453341500.

The previous prime is 12503155103. The next prime is 12503155163. The reversal of 12503155117 is 71155130521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12503155117 - 227 = 12368937389 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12503155187) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24906433 + ... + 24906934.

It is an arithmetic number, because the mean of its divisors is an integer number (3138242184).

Almost surely, 212503155117 is an apocalyptic number.

It is an amenable number.

12503155117 is a deficient number, since it is larger than the sum of its proper divisors (49813619).

12503155117 is an equidigital number, since it uses as much as digits as its factorization.

12503155117 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 49813618.

The product of its (nonzero) digits is 5250, while the sum is 31.

Adding to 12503155117 its reverse (71155130521), we get a palindrome (83658285638).

The spelling of 12503155117 in words is "twelve billion, five hundred three million, one hundred fifty-five thousand, one hundred seventeen".

Divisors: 1 251 49813367 12503155117