Base | Representation |
---|---|
bin | 1011010111110010001101… |
… | …0110111011100001101011 |
3 | 1122021022001111120220110001 |
4 | 2311330203112323201223 |
5 | 3114323120202342303 |
6 | 42331524402203431 |
7 | 2430221006024056 |
oct | 265744326734153 |
9 | 48238044526401 |
10 | 12503243012203 |
11 | 3a906607a3379 |
12 | 149b266953577 |
13 | 6c9087688a98 |
14 | 3132357c5a9d |
15 | 16a3885eb31d |
hex | b5f235bb86b |
12503243012203 has 4 divisors (see below), whose sum is σ = 12593194400920. Its totient is φ = 12413291623488.
The previous prime is 12503243012107. The next prime is 12503243012263. The reversal of 12503243012203 is 30221034230521.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12503243012203 - 233 = 12494653077611 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12503243012263) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44975694150 + ... + 44975694427.
It is an arithmetic number, because the mean of its divisors is an integer number (3148298600230).
Almost surely, 212503243012203 is an apocalyptic number.
12503243012203 is a deficient number, since it is larger than the sum of its proper divisors (89951388717).
12503243012203 is an equidigital number, since it uses as much as digits as its factorization.
12503243012203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 89951388716.
The product of its (nonzero) digits is 8640, while the sum is 28.
Adding to 12503243012203 its reverse (30221034230521), we get a palindrome (42724277242724).
The spelling of 12503243012203 in words is "twelve trillion, five hundred three billion, two hundred forty-three million, twelve thousand, two hundred three".
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