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12503400015 = 351943871579
BaseRepresentation
bin10111010010100001…
…01011111001001111
31012021101100112100110
423221100223321033
5201101332300030
65424411131103
7621563101161
oct135120537117
935241315313
1012503400015
115336930547
12250b443a93
13124353a362
1486881a931
154d2a5b1b0
hex2e942be4f

12503400015 has 16 divisors (see below), whose sum is σ = 21058358400. Its totient is φ = 6317507232.

The previous prime is 12503399929. The next prime is 12503400043. The reversal of 12503400015 is 51000430521.

It is not a de Polignac number, because 12503400015 - 214 = 12503383631 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12503399964 and 12503400000.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 21935505 + ... + 21936074.

It is an arithmetic number, because the mean of its divisors is an integer number (1316147400).

Almost surely, 212503400015 is an apocalyptic number.

12503400015 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

12503400015 is a deficient number, since it is larger than the sum of its proper divisors (8554958385).

12503400015 is a wasteful number, since it uses less digits than its factorization.

12503400015 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43871606.

The product of its (nonzero) digits is 600, while the sum is 21.

Adding to 12503400015 its reverse (51000430521), we get a palindrome (63503830536).

The spelling of 12503400015 in words is "twelve billion, five hundred three million, four hundred thousand, fifteen".

Divisors: 1 3 5 15 19 57 95 285 43871579 131614737 219357895 658073685 833560001 2500680003 4167800005 12503400015