Base | Representation |
---|---|
bin | 10111010010100110… |
… | …00110111100111101 |
3 | 1012021102112210120100 |
4 | 23221103012330331 |
5 | 201102013111013 |
6 | 5424432511313 |
7 | 621601354632 |
oct | 135123067475 |
9 | 35242483510 |
10 | 12504035133 |
11 | 5337224737 |
12 | 250b6ab539 |
13 | 1243700475 |
14 | 868944189 |
15 | 4d2b34473 |
hex | 2e94c6f3d |
12504035133 has 6 divisors (see below), whose sum is σ = 18061384094. Its totient is φ = 8336023416.
The previous prime is 12504035129. The next prime is 12504035149. The reversal of 12504035133 is 33153040521.
12504035133 is a `hidden beast` number, since 1 + 250 + 403 + 5 + 1 + 3 + 3 = 666.
It can be written as a sum of positive squares in only one way, i.e., 10874944089 + 1629091044 = 104283^2 + 40362^2 .
It is not a de Polignac number, because 12504035133 - 22 = 12504035129 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12504035097 and 12504035106.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12504034133) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 694668610 + ... + 694668627.
Almost surely, 212504035133 is an apocalyptic number.
It is an amenable number.
12504035133 is a deficient number, since it is larger than the sum of its proper divisors (5557348961).
12504035133 is a wasteful number, since it uses less digits than its factorization.
12504035133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1389337243 (or 1389337240 counting only the distinct ones).
The product of its (nonzero) digits is 5400, while the sum is 27.
Adding to 12504035133 its reverse (33153040521), we get a palindrome (45657075654).
The spelling of 12504035133 in words is "twelve billion, five hundred four million, thirty-five thousand, one hundred thirty-three".
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