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12504315255 = 355931405769
BaseRepresentation
bin10111010010101000…
…01011010101110111
31012021110002000211020
423221110023111313
5201102101042010
65424442512223
7621603632415
oct135124132567
935243060736
1012504315255
1153373a6143
12250b805673
13124379ab13
148689b82b5
154d2b8c470
hex2e950b577

12504315255 has 16 divisors (see below), whose sum is σ = 20040657120. Its totient is φ = 6657717248.

The previous prime is 12504315251. The next prime is 12504315277. The reversal of 12504315255 is 55251340521.

It is a cyclic number.

It is not a de Polignac number, because 12504315255 - 22 = 12504315251 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12504315251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 693990 + ... + 711779.

It is an arithmetic number, because the mean of its divisors is an integer number (1252541070).

Almost surely, 212504315255 is an apocalyptic number.

12504315255 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

12504315255 is a deficient number, since it is larger than the sum of its proper divisors (7536341865).

12504315255 is a wasteful number, since it uses less digits than its factorization.

12504315255 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1406370.

The product of its (nonzero) digits is 30000, while the sum is 33.

Adding to 12504315255 its reverse (55251340521), we get a palindrome (67755655776).

The spelling of 12504315255 in words is "twelve billion, five hundred four million, three hundred fifteen thousand, two hundred fifty-five".

Divisors: 1 3 5 15 593 1779 2965 8895 1405769 4217307 7028845 21086535 833621017 2500863051 4168105085 12504315255