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12506441143 = 71786634449
BaseRepresentation
bin10111010010111000…
…10010010110110111
31012021121002000222211
423221130102112313
5201103122104033
65425000234251
7621630665350
oct135134222667
935247060884
1012506441143
115338618379
12251046b987
131244063641
14868dacd27
154d2e5c2cd
hex2e97125b7

12506441143 has 4 divisors (see below), whose sum is σ = 14293075600. Its totient is φ = 10719806688.

The previous prime is 12506441069. The next prime is 12506441147. The reversal of 12506441143 is 34114460521.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12506441143 is a prime.

It is a super-2 number, since 2×125064411432 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12506441147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 893317218 + ... + 893317231.

It is an arithmetic number, because the mean of its divisors is an integer number (3573268900).

Almost surely, 212506441143 is an apocalyptic number.

12506441143 is a deficient number, since it is larger than the sum of its proper divisors (1786634457).

12506441143 is an equidigital number, since it uses as much as digits as its factorization.

12506441143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1786634456.

The product of its (nonzero) digits is 11520, while the sum is 31.

The spelling of 12506441143 in words is "twelve billion, five hundred six million, four hundred forty-one thousand, one hundred forty-three".

Divisors: 1 7 1786634449 12506441143