Search a number
-
+
125100332013 = 341700110671
BaseRepresentation
bin111010010000010001…
…1111001001111101101
3102221220110100022201010
41310200203321033231
54022201141111023
6133245330135433
712016050164016
oct1644043711755
9387813308633
10125100332013
1149066970048
12202b3a21579
13ba48a748c7
1460aa88400d
1533c2b2a093
hex1d208f93ed

125100332013 has 4 divisors (see below), whose sum is σ = 166800442688. Its totient is φ = 83400221340.

The previous prime is 125100331963. The next prime is 125100332017. The reversal of 125100332013 is 310233001521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 310233001521 = 3103411000507.

It is not a de Polignac number, because 125100332013 - 29 = 125100331501 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (125100332017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20850055333 + ... + 20850055338.

It is an arithmetic number, because the mean of its divisors is an integer number (41700110672).

Almost surely, 2125100332013 is an apocalyptic number.

It is an amenable number.

125100332013 is a deficient number, since it is larger than the sum of its proper divisors (41700110675).

125100332013 is an equidigital number, since it uses as much as digits as its factorization.

125100332013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 41700110674.

The product of its (nonzero) digits is 540, while the sum is 21.

Adding to 125100332013 its reverse (310233001521), we get a palindrome (435333333534).

The spelling of 125100332013 in words is "one hundred twenty-five billion, one hundred million, three hundred thirty-two thousand, thirteen".

Divisors: 1 3 41700110671 125100332013