Base | Representation |
---|---|
bin | 10111010011010110… |
… | …11100100101110111 |
3 | 1012021212112221101222 |
4 | 23221223130211313 |
5 | 201110131241343 |
6 | 5425221340555 |
7 | 622006526525 |
oct | 135153344567 |
9 | 35255487358 |
10 | 12510415223 |
11 | 533a892139 |
12 | 251186775b |
13 | 1244b25477 |
14 | 869725315 |
15 | 4d3494a68 |
hex | 2e9adc977 |
12510415223 has 4 divisors (see below), whose sum is σ = 12681790848. Its totient is φ = 12339039600.
The previous prime is 12510415219. The next prime is 12510415261. The reversal of 12510415223 is 32251401521.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12510415223 - 22 = 12510415219 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12510415192 and 12510415201.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12510415213) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85687703 + ... + 85687848.
It is an arithmetic number, because the mean of its divisors is an integer number (3170447712).
Almost surely, 212510415223 is an apocalyptic number.
12510415223 is a deficient number, since it is larger than the sum of its proper divisors (171375625).
12510415223 is an equidigital number, since it uses as much as digits as its factorization.
12510415223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 171375624.
The product of its (nonzero) digits is 2400, while the sum is 26.
Adding to 12510415223 its reverse (32251401521), we get a palindrome (44761816744).
The spelling of 12510415223 in words is "twelve billion, five hundred ten million, four hundred fifteen thousand, two hundred twenty-three".
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