Search a number
-
+
12511315143 = 321390146127
BaseRepresentation
bin10111010011011101…
…11000010011000111
31012021221020122212100
423221232320103013
5201110344041033
65425252523143
7622020265305
oct135156702307
935257218770
1012511315143
115340347278
1225120204b3
13124507bc72
148698bb275
154d35c1513
hex2e9bb84c7

12511315143 has 6 divisors (see below), whose sum is σ = 18071899664. Its totient is φ = 8340876756.

The previous prime is 12511315133. The next prime is 12511315199. The reversal of 12511315143 is 34151311521.

12511315143 is a `hidden beast` number, since 1 + 2 + 511 + 3 + 1 + 5 + 143 = 666.

It is not a de Polignac number, because 12511315143 - 28 = 12511314887 is a prime.

It is a super-2 number, since 2×125113151432 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12511315133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 695073055 + ... + 695073072.

Almost surely, 212511315143 is an apocalyptic number.

12511315143 is a deficient number, since it is larger than the sum of its proper divisors (5560584521).

12511315143 is a wasteful number, since it uses less digits than its factorization.

12511315143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1390146133 (or 1390146130 counting only the distinct ones).

The product of its digits is 1800, while the sum is 27.

Adding to 12511315143 its reverse (34151311521), we get a palindrome (46662626664).

The spelling of 12511315143 in words is "twelve billion, five hundred eleven million, three hundred fifteen thousand, one hundred forty-three".

Divisors: 1 3 9 1390146127 4170438381 12511315143