12511342153133 has 4 divisors (see below), whose sum is σ = 12511350802368. Its totient is φ = 12511333503900.

The previous prime is 12511342153049. The next prime is 12511342153139. The reversal of 12511342153133 is 33135124311521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 12511342153133 - 2¹⁶ = 12511342087597 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12511342153093 and 12511342153102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12511342153139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1569941 + ... + 5242842.

It is an arithmetic number, because the mean of its divisors is an integer number (3127837700592).

Almost surely, 2^{12511342153133} is an apocalyptic number.

It is an amenable number.

12511342153133 is a deficient number, since it is larger than the sum of its proper divisors (8649235).

12511342153133 is an equidigital number, since it uses as much as digits as its factorization.

12511342153133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8649234.

The product of its digits is 32400, while the sum is 35.

Adding to 12511342153133 its reverse (33135124311521), we get a palindrome (45646466464654).

The spelling of 12511342153133 in words is "twelve trillion, five hundred eleven billion, three hundred forty-two million, one hundred fifty-three thousand, one hundred thirty-three".