125120325441 has 4 divisors (see below), whose sum is σ = 166827100592. Its totient is φ = 83413550292.

The previous prime is 125120325433. The next prime is 125120325469. The reversal of 125120325441 is 144523021521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 125120325441 - 2³ = 125120325433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 125120325399 and 125120325408.

It is not an unprimeable number, because it can be changed into a prime (125120325241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20853387571 + ... + 20853387576.

It is an arithmetic number, because the mean of its divisors is an integer number (41706775148).

Almost surely, 2^125120325441 is an apocalyptic number.

It is an amenable number.

125120325441 is a deficient number, since it is larger than the sum of its proper divisors (41706775151).

125120325441 is an equidigital number, since it uses as much as digits as its factorization.

125120325441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 41706775150.

The product of its (nonzero) digits is 9600, while the sum is 30.

Adding to 125120325441 its reverse (144523021521), we get a palindrome (269643346962).

The spelling of 125120325441 in words is "one hundred twenty-five billion, one hundred twenty million, three hundred twenty-five thousand, four hundred forty-one".