12512042555533 has 4 divisors (see below), whose sum is σ = 12517635781980. Its totient is φ = 12506449329088.

The previous prime is 12512042555521. The next prime is 12512042555567. The reversal of 12512042555533 is 33555524021521.

12512042555533 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 9324882146889 + 3187160408644 = 3053667^2 + 1785262^2 .

It is a cyclic number.

It is not a de Polignac number, because 12512042555533 - 2¹⁷ = 12512042424461 is a prime.

It is a super-2 number, since 2×12512042555533² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12512042555533.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12512042555503) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2796609868 + ... + 2796614341.

It is an arithmetic number, because the mean of its divisors is an integer number (3129408945495).

Almost surely, 2^{12512042555533} is an apocalyptic number.

It is an amenable number.

12512042555533 is a deficient number, since it is larger than the sum of its proper divisors (5593226447).

12512042555533 is an equidigital number, since it uses as much as digits as its factorization.

12512042555533 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5593226446.

The product of its (nonzero) digits is 900000, while the sum is 43.

The spelling of 12512042555533 in words is "twelve trillion, five hundred twelve billion, forty-two million, five hundred fifty-five thousand, five hundred thirty-three".