Base | Representation |
---|---|
bin | 111010010000111010… |
… | …1000010111100011011 |
3 | 102221221221101010022110 |
4 | 1310201311002330123 |
5 | 4022222112333103 |
6 | 133251410123403 |
7 | 12016426045404 |
oct | 1644165027433 |
9 | 387857333273 |
10 | 125121605403 |
11 | 49077980063 |
12 | 202bab80563 |
13 | ba502b2802 |
14 | 60ad6209ab |
15 | 33c492d403 |
hex | 1d21d42f1b |
125121605403 has 4 divisors (see below), whose sum is σ = 166828807208. Its totient is φ = 83414403600.
The previous prime is 125121605381. The next prime is 125121605449. The reversal of 125121605403 is 304506121521.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 125121605403 - 26 = 125121605339 is a prime.
It is a super-2 number, since 2×1251216054032 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (125121605473) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20853600898 + ... + 20853600903.
It is an arithmetic number, because the mean of its divisors is an integer number (41707201802).
Almost surely, 2125121605403 is an apocalyptic number.
125121605403 is a deficient number, since it is larger than the sum of its proper divisors (41707201805).
125121605403 is an equidigital number, since it uses as much as digits as its factorization.
125121605403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 41707201804.
The product of its (nonzero) digits is 7200, while the sum is 30.
Adding to 125121605403 its reverse (304506121521), we get a palindrome (429627726924).
The spelling of 125121605403 in words is "one hundred twenty-five billion, one hundred twenty-one million, six hundred five thousand, four hundred three".
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