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12512233453 = 42192965687
BaseRepresentation
bin10111010011100100…
…11000011111101101
31012021222222022112211
423221302120133231
5201111112432303
65425324330421
7622031141506
oct135162303755
935258868484
1012512233453
115340914205
1225123a3a11
131245310c45
14869a79bad
154d370366d
hex2e9c987ed

12512233453 has 4 divisors (see below), whose sum is σ = 12515203360. Its totient is φ = 12509263548.

The previous prime is 12512233411. The next prime is 12512233463. The reversal of 12512233453 is 35433221521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35433221521 = 107331151603.

It is a cyclic number.

It is not a de Polignac number, because 12512233453 - 217 = 12512102381 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12512233463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1478625 + ... + 1487062.

It is an arithmetic number, because the mean of its divisors is an integer number (3128800840).

Almost surely, 212512233453 is an apocalyptic number.

It is an amenable number.

12512233453 is a deficient number, since it is larger than the sum of its proper divisors (2969907).

12512233453 is an equidigital number, since it uses as much as digits as its factorization.

12512233453 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2969906.

The product of its digits is 21600, while the sum is 31.

Adding to 12512233453 its reverse (35433221521), we get a palindrome (47945454974).

The spelling of 12512233453 in words is "twelve billion, five hundred twelve million, two hundred thirty-three thousand, four hundred fifty-three".

Divisors: 1 4219 2965687 12512233453