12512341353 has 4 divisors (see below), whose sum is σ = 16683121808. Its totient is φ = 8341560900.

The previous prime is 12512341349. The next prime is 12512341357. The reversal of 12512341353 is 35314321521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (12512341349) and next prime (12512341357).

It is not a de Polignac number, because 12512341353 - 2² = 12512341349 is a prime.

It is a super-2 number, since 2×12512341353² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 12512341353.

It is not an unprimeable number, because it can be changed into a prime (12512341357) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2085390223 + ... + 2085390228.

It is an arithmetic number, because the mean of its divisors is an integer number (4170780452).

Almost surely, 2^12512341353 is an apocalyptic number.

It is an amenable number.

12512341353 is a deficient number, since it is larger than the sum of its proper divisors (4170780455).

12512341353 is an equidigital number, since it uses as much as digits as its factorization.

12512341353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4170780454.

The product of its digits is 10800, while the sum is 30.

Adding to 12512341353 its reverse (35314321521), we get a palindrome (47826662874).

The spelling of 12512341353 in words is "twelve billion, five hundred twelve million, three hundred forty-one thousand, three hundred fifty-three".