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12513405442 = 26256702721
BaseRepresentation
bin10111010011101101…
…10110101000000010
31012022002011212012211
423221312312220002
5201111412433232
65425405412334
7622044122416
oct135166665002
935262155184
1012513405442
11534154479a
12251286a0aa
131245631525
14869ca2d46
154d3885a47
hex2e9db6a02

12513405442 has 4 divisors (see below), whose sum is σ = 18770108166. Its totient is φ = 6256702720.

The previous prime is 12513405397. The next prime is 12513405467. The reversal of 12513405442 is 24450431521.

12513405442 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 12432027001 + 81378441 = 111499^2 + 9021^2 .

It is a super-4 number, since 4×125134054424 (a number of 41 digits) contains 4444 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3128351359 + ... + 3128351362.

Almost surely, 212513405442 is an apocalyptic number.

12513405442 is a deficient number, since it is larger than the sum of its proper divisors (6256702724).

12513405442 is an equidigital number, since it uses as much as digits as its factorization.

12513405442 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6256702723.

The product of its (nonzero) digits is 19200, while the sum is 31.

Adding to 12513405442 its reverse (24450431521), we get a palindrome (36963836963).

The spelling of 12513405442 in words is "twelve billion, five hundred thirteen million, four hundred five thousand, four hundred forty-two".

Divisors: 1 2 6256702721 12513405442