Base | Representation |
---|---|
bin | 10010001101011001111… |
… | …011011100110110101001 |
3 | 11102121221022221202021111 |
4 | 102031121323130312221 |
5 | 131000223111140131 |
6 | 2354505401510321 |
7 | 156256322353660 |
oct | 22153173346651 |
9 | 4377838852244 |
10 | 1251344240041 |
11 | 442768223625 |
12 | 1826287a23a1 |
13 | 910029b212c |
14 | 447cb5b3dd7 |
15 | 2283c5adab1 |
hex | 12359edcda9 |
1251344240041 has 16 divisors (see below), whose sum is σ = 1449210801024. Its totient is φ = 1058286898944.
The previous prime is 1251344239973. The next prime is 1251344240117. The reversal of 1251344240041 is 1400424431521.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 1251344240041 - 211 = 1251344237993 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1251344239985 and 1251344240012.
It is not an unprimeable number, because it can be changed into a prime (1251344240141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 944016 + ... + 1842241.
It is an arithmetic number, because the mean of its divisors is an integer number (90575675064).
Almost surely, 21251344240041 is an apocalyptic number.
It is an amenable number.
1251344240041 is a deficient number, since it is larger than the sum of its proper divisors (197866560983).
1251344240041 is an equidigital number, since it uses as much as digits as its factorization.
1251344240041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2787120.
The product of its (nonzero) digits is 15360, while the sum is 31.
Adding to 1251344240041 its reverse (1400424431521), we get a palindrome (2651768671562).
The spelling of 1251344240041 in words is "one trillion, two hundred fifty-one billion, three hundred forty-four million, two hundred forty thousand, forty-one".
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