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125135456151 = 341711818717
BaseRepresentation
bin111010010001010100…
…1111000011110010111
3102221222220102210222010
41310202221320132113
54022234134044101
6133253023035303
712016654553526
oct1644251703627
9387886383863
10125135456151
1149084780362
122030373bb33
13ba53122014
1460b13c84bd
1533c5c672d6
hex1d22a78797

125135456151 has 4 divisors (see below), whose sum is σ = 166847274872. Its totient is φ = 83423637432.

The previous prime is 125135456137. The next prime is 125135456249. The reversal of 125135456151 is 151654531521.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 125135456151 - 25 = 125135456119 is a prime.

It is a super-2 number, since 2×1251354561512 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (125135456101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20855909356 + ... + 20855909361.

It is an arithmetic number, because the mean of its divisors is an integer number (41711818718).

Almost surely, 2125135456151 is an apocalyptic number.

125135456151 is a deficient number, since it is larger than the sum of its proper divisors (41711818721).

125135456151 is an equidigital number, since it uses as much as digits as its factorization.

125135456151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 41711818720.

The product of its digits is 90000, while the sum is 39.

Adding to 125135456151 its reverse (151654531521), we get a palindrome (276789987672).

The spelling of 125135456151 in words is "one hundred twenty-five billion, one hundred thirty-five million, four hundred fifty-six thousand, one hundred fifty-one".

Divisors: 1 3 41711818717 125135456151