12514115544439 has 4 divisors (see below), whose sum is σ = 13058207524656. Its totient is φ = 11970023564224.

The previous prime is 12514115544431. The next prime is 12514115544461. The reversal of 12514115544439 is 93444551141521.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12514115544439 - 2³ = 12514115544431 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12514115544392 and 12514115544401.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12514115544431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 272045990074 + ... + 272045990119.

It is an arithmetic number, because the mean of its divisors is an integer number (3264551881164).

Almost surely, 2^{12514115544439} is an apocalyptic number.

12514115544439 is a deficient number, since it is larger than the sum of its proper divisors (544091980217).

12514115544439 is an equidigital number, since it uses as much as digits as its factorization.

12514115544439 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 544091980216.

The product of its digits is 1728000, while the sum is 49.

The spelling of 12514115544439 in words is "twelve trillion, five hundred fourteen billion, one hundred fifteen million, five hundred forty-four thousand, four hundred thirty-nine".