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12514453453 = 31873926719
BaseRepresentation
bin10111010011110101…
…10110011111001101
31012022011011002211001
423221322312133031
5201112200002303
65425444100301
7622056046015
oct135172663715
935264132731
1012514453453
1153420a0117
122513094691
13124590a558
1486a096c45
154d39e131d
hex2e9eb67cd

12514453453 has 4 divisors (see below), whose sum is σ = 12518383360. Its totient is φ = 12510523548.

The previous prime is 12514453451. The next prime is 12514453459. The reversal of 12514453453 is 35435441521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12514453453 - 21 = 12514453451 is a prime.

It is a super-2 number, since 2×125144534532 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12514453451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1960173 + ... + 1966546.

It is an arithmetic number, because the mean of its divisors is an integer number (3129595840).

Almost surely, 212514453453 is an apocalyptic number.

It is an amenable number.

12514453453 is a deficient number, since it is larger than the sum of its proper divisors (3929907).

12514453453 is an equidigital number, since it uses as much as digits as its factorization.

12514453453 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3929906.

The product of its digits is 144000, while the sum is 37.

Adding to 12514453453 its reverse (35435441521), we get a palindrome (47949894974).

The spelling of 12514453453 in words is "twelve billion, five hundred fourteen million, four hundred fifty-three thousand, four hundred fifty-three".

Divisors: 1 3187 3926719 12514453453