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1251530102234 = 2625765051117
BaseRepresentation
bin10010001101100101000…
…000011101010111011010
311102122102021200112021102
4102031211000131113122
5131001113201232414
62354540041311402
7156264040226156
oct22154500352732
94378367615242
101251530102234
1144285312a645
1218267aa95562
1391032359369
1444808156066
152284da73ede
hex1236501d5da

1251530102234 has 4 divisors (see below), whose sum is σ = 1877295153354. Its totient is φ = 625765051116.

The previous prime is 1251530102213. The next prime is 1251530102257. The reversal of 1251530102234 is 4322010351521.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 831282592009 + 420247510225 = 911747^2 + 648265^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1251530102197 and 1251530102206.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 312882525557 + ... + 312882525560.

Almost surely, 21251530102234 is an apocalyptic number.

1251530102234 is a deficient number, since it is larger than the sum of its proper divisors (625765051120).

1251530102234 is an equidigital number, since it uses as much as digits as its factorization.

1251530102234 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 625765051119.

The product of its (nonzero) digits is 7200, while the sum is 29.

Adding to 1251530102234 its reverse (4322010351521), we get a palindrome (5573540453755).

The spelling of 1251530102234 in words is "one trillion, two hundred fifty-one billion, five hundred thirty million, one hundred two thousand, two hundred thirty-four".

Divisors: 1 2 625765051117 1251530102234