12517040333 has 4 divisors (see below), whose sum is σ = 14305188960. Its totient is φ = 10728891708.

The previous prime is 12517040317. The next prime is 12517040387. The reversal of 12517040333 is 33304071521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12517040333 - 2⁴ = 12517040317 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12517040296 and 12517040305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12517040303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 894074303 + ... + 894074316.

It is an arithmetic number, because the mean of its divisors is an integer number (3576297240).

Almost surely, 2^12517040333 is an apocalyptic number.

It is an amenable number.

12517040333 is a deficient number, since it is larger than the sum of its proper divisors (1788148627).

12517040333 is an equidigital number, since it uses as much as digits as its factorization.

12517040333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1788148626.

The product of its (nonzero) digits is 7560, while the sum is 29.

The spelling of 12517040333 in words is "twelve billion, five hundred seventeen million, forty thousand, three hundred thirty-three".