Base | Representation |
---|---|
bin | 10111010100011100… |
… | …00000010000100101 |
3 | 1012022111121012000010 |
4 | 23222032000100211 |
5 | 201114441133323 |
6 | 5430143440433 |
7 | 622146526551 |
oct | 135216002045 |
9 | 35274535003 |
10 | 12519474213 |
11 | 5344a0a304 |
12 | 25148b6119 |
13 | 124697790c |
14 | 86aa02861 |
15 | 4d4183c93 |
hex | 2ea380425 |
12519474213 has 4 divisors (see below), whose sum is σ = 16692632288. Its totient is φ = 8346316140.
The previous prime is 12519474193. The next prime is 12519474223. The reversal of 12519474213 is 31247491521.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31247491521 = 3 ⋅10415830507.
It is not a de Polignac number, because 12519474213 - 214 = 12519457829 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12519474223) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2086579033 + ... + 2086579038.
It is an arithmetic number, because the mean of its divisors is an integer number (4173158072).
Almost surely, 212519474213 is an apocalyptic number.
It is an amenable number.
12519474213 is a deficient number, since it is larger than the sum of its proper divisors (4173158075).
12519474213 is an equidigital number, since it uses as much as digits as its factorization.
12519474213 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4173158074.
The product of its digits is 60480, while the sum is 39.
The spelling of 12519474213 in words is "twelve billion, five hundred nineteen million, four hundred seventy-four thousand, two hundred thirteen".
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