Base | Representation |
---|---|
bin | 111010010100001110… |
… | …0010001100101101101 |
3 | 102222020200010210211211 |
4 | 1310220130101211231 |
5 | 4022434013133201 |
6 | 133310412114421 |
7 | 12022244062633 |
oct | 1645034214555 |
9 | 388220123754 |
10 | 125232552301 |
11 | 4912456910a |
12 | 20330165a11 |
13 | ba6a289b6c |
14 | 60c0261353 |
15 | 33ce546651 |
hex | 1d2871196d |
125232552301 has 4 divisors (see below), whose sum is σ = 126061907104. Its totient is φ = 124403197500.
The previous prime is 125232552239. The next prime is 125232552311. The reversal of 125232552301 is 103255232521.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 103255232521 = 7 ⋅14750747503.
It is a cyclic number.
It is not a de Polignac number, because 125232552301 - 211 = 125232550253 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (125232552311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 414677175 + ... + 414677476.
It is an arithmetic number, because the mean of its divisors is an integer number (31515476776).
Almost surely, 2125232552301 is an apocalyptic number.
It is an amenable number.
125232552301 is a deficient number, since it is larger than the sum of its proper divisors (829354803).
125232552301 is an equidigital number, since it uses as much as digits as its factorization.
125232552301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 829354802.
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 125232552301 its reverse (103255232521), we get a palindrome (228487784822).
The spelling of 125232552301 in words is "one hundred twenty-five billion, two hundred thirty-two million, five hundred fifty-two thousand, three hundred one".
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