12523504234303 has 4 divisors (see below), whose sum is σ = 12523513485280. Its totient is φ = 12523494983328.

The previous prime is 12523504234301. The next prime is 12523504234327. The reversal of 12523504234303 is 30343240532521.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 12523504234303 - 2¹ = 12523504234301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12523504234301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2155050 + ... + 5448967.

It is an arithmetic number, because the mean of its divisors is an integer number (3130878371320).

Almost surely, 2^{12523504234303} is an apocalyptic number.

12523504234303 is a deficient number, since it is larger than the sum of its proper divisors (9250977).

12523504234303 is an equidigital number, since it uses as much as digits as its factorization.

12523504234303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9250976.

The product of its (nonzero) digits is 259200, while the sum is 37.

Adding to 12523504234303 its reverse (30343240532521), we get a palindrome (42866744766824).

The spelling of 12523504234303 in words is "twelve trillion, five hundred twenty-three billion, five hundred four million, two hundred thirty-four thousand, three hundred three".