Base | Representation |
---|---|
bin | 10111010100111011… |
… | …11100100101000101 |
3 | 1012022210110111211111 |
4 | 23222131330211011 |
5 | 201122023402240 |
6 | 5430413205021 |
7 | 622230204112 |
oct | 135235744505 |
9 | 35283414744 |
10 | 12523653445 |
11 | 5347304216 |
12 | 2516190771 |
13 | 12477abc34 |
14 | 86b3ad909 |
15 | 4d470c1ea |
hex | 2ea77c945 |
12523653445 has 16 divisors (see below), whose sum is σ = 15841440000. Its totient is φ = 9478358208.
The previous prime is 12523653419. The next prime is 12523653523. The reversal of 12523653445 is 54435632521.
It is a cyclic number.
It is not a de Polignac number, because 12523653445 - 233 = 3933718853 is a prime.
It is a super-2 number, since 2×125236534452 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12523653398 and 12523653407.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 23370 + ... + 159979.
It is an arithmetic number, because the mean of its divisors is an integer number (990090000).
Almost surely, 212523653445 is an apocalyptic number.
It is an amenable number.
12523653445 is a deficient number, since it is larger than the sum of its proper divisors (3317786555).
12523653445 is a wasteful number, since it uses less digits than its factorization.
12523653445 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 184092.
The product of its digits is 432000, while the sum is 40.
The spelling of 12523653445 in words is "twelve billion, five hundred twenty-three million, six hundred fifty-three thousand, four hundred forty-five".
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