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125240654010613 = 1051119163324463
BaseRepresentation
bin11100011110011111011100…
…101100011001100011110101
3121102102220000111212120020211
4130132133130230121203311
5112403420324411314423
61122210432344025421
735244224105243521
oct3436373454314365
9542386014776224
10125240654010613
11369a6299198849
1212068589762271
1354b61b221bc8b
1422cd973caad81
15e72be441e10d
hex71e7dcb198f5

125240654010613 has 4 divisors (see below), whose sum is σ = 125359817336128. Its totient is φ = 125121490685100.

The previous prime is 125240654010533. The next prime is 125240654010643. The reversal of 125240654010613 is 316010456042521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 125240654010613 - 217 = 125240653879541 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (125240654010643) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59581661181 + ... + 59581663282.

It is an arithmetic number, because the mean of its divisors is an integer number (31339954334032).

Almost surely, 2125240654010613 is an apocalyptic number.

It is an amenable number.

125240654010613 is a deficient number, since it is larger than the sum of its proper divisors (119163325515).

125240654010613 is a wasteful number, since it uses less digits than its factorization.

125240654010613 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 119163325514.

The product of its (nonzero) digits is 172800, while the sum is 40.

The spelling of 125240654010613 in words is "one hundred twenty-five trillion, two hundred forty billion, six hundred fifty-four million, ten thousand, six hundred thirteen".

Divisors: 1 1051 119163324463 125240654010613