1252451024133 has 4 divisors (see below), whose sum is σ = 1669934698848. Its totient is φ = 834967349420.

The previous prime is 1252451024131. The next prime is 1252451024137. The reversal of 1252451024133 is 3314201542521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1252451024133 - 2¹ = 1252451024131 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1252451024094 and 1252451024103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1252451024131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 208741837353 + ... + 208741837358.

It is an arithmetic number, because the mean of its divisors is an integer number (417483674712).

Almost surely, 2^{1252451024133} is an apocalyptic number.

It is an amenable number.

1252451024133 is a deficient number, since it is larger than the sum of its proper divisors (417483674715).

1252451024133 is an equidigital number, since it uses as much as digits as its factorization.

1252451024133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 417483674714.

The product of its (nonzero) digits is 28800, while the sum is 33.

Adding to 1252451024133 its reverse (3314201542521), we get a palindrome (4566652566654).

The spelling of 1252451024133 in words is "one trillion, two hundred fifty-two billion, four hundred fifty-one million, twenty-four thousand, one hundred thirty-three".