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1252452500421 = 3417484166807
BaseRepresentation
bin10010001110011011111…
…111001000001111000101
311102201210120100012201020
4102032123333020033011
5131010010320003141
62355211351421353
7156325640412543
oct22163377101705
94381716305636
101252452500421
1144318686aaa1
12182897984859
139114b4958c5
1444894862d93
15228a4a27266
hex1239bfc83c5

1252452500421 has 4 divisors (see below), whose sum is σ = 1669936667232. Its totient is φ = 834968333612.

The previous prime is 1252452500399. The next prime is 1252452500441. The reversal of 1252452500421 is 1240052542521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1252452500421 - 217 = 1252452369349 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1252452500441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 208742083401 + ... + 208742083406.

It is an arithmetic number, because the mean of its divisors is an integer number (417484166808).

Almost surely, 21252452500421 is an apocalyptic number.

It is an amenable number.

1252452500421 is a deficient number, since it is larger than the sum of its proper divisors (417484166811).

1252452500421 is an equidigital number, since it uses as much as digits as its factorization.

1252452500421 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 417484166810.

The product of its (nonzero) digits is 32000, while the sum is 33.

The spelling of 1252452500421 in words is "one trillion, two hundred fifty-two billion, four hundred fifty-two million, five hundred thousand, four hundred twenty-one".

Divisors: 1 3 417484166807 1252452500421