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125253435021314 = 2493112700611947
BaseRepresentation
bin11100011110101011010110…
…100000000101100000000010
3121102111010000020121011212112
4130132223112200011200002
5112404123013331140224
61122220344513255322
735245155612114425
oct3436532640054002
9542433006534775
10125253435021314
1136a007577a0306
121206ab55b64542
1354b746b1182c2
1422d042750d9bc
15e731e151530e
hex71ead6805802

125253435021314 has 8 divisors (see below), whose sum is σ = 187918254382608. Its totient is φ = 62614016893780.

The previous prime is 125253435021293. The next prime is 125253435021353. The reversal of 125253435021314 is 413120534352521.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×1252534350213143 (a number of 43 digits) contains 333 as substring.

It is a Curzon number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6350296112 + ... + 6350315835.

It is an arithmetic number, because the mean of its divisors is an integer number (23489781797826).

Almost surely, 2125253435021314 is an apocalyptic number.

125253435021314 is a deficient number, since it is larger than the sum of its proper divisors (62664819361294).

125253435021314 is a wasteful number, since it uses less digits than its factorization.

125253435021314 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12700616880.

The product of its (nonzero) digits is 432000, while the sum is 41.

Adding to 125253435021314 its reverse (413120534352521), we get a palindrome (538373969373835).

The spelling of 125253435021314 in words is "one hundred twenty-five trillion, two hundred fifty-three billion, four hundred thirty-five million, twenty-one thousand, three hundred fourteen".

Divisors: 1 2 4931 9862 12700611947 25401223894 62626717510657 125253435021314