Base | Representation |
---|---|
bin | 1011011001000101001100… |
… | …1111001100000000011011 |
3 | 1122100102120002210022111202 |
4 | 2312101103033030000123 |
5 | 3120204231402003103 |
6 | 42350051151344415 |
7 | 2431640042614316 |
oct | 266212317140033 |
9 | 48312502708452 |
10 | 12525521125403 |
11 | 3a9a053154580 |
12 | 14a364382210b |
13 | 6cb1c80146a0 |
14 | 31434a47d97d |
15 | 16ac3e363988 |
hex | b64533cc01b |
12525521125403 has 16 divisors (see below), whose sum is σ = 14715671310816. Its totient is φ = 10510659843840.
The previous prime is 12525521125367. The next prime is 12525521125417. The reversal of 12525521125403 is 30452112552521.
It is not a de Polignac number, because 12525521125403 - 218 = 12525520863259 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12525521125303) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4640951 + ... + 6825647.
It is an arithmetic number, because the mean of its divisors is an integer number (919729456926).
Almost surely, 212525521125403 is an apocalyptic number.
12525521125403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
12525521125403 is a deficient number, since it is larger than the sum of its proper divisors (2190150185413).
12525521125403 is a wasteful number, since it uses less digits than its factorization.
12525521125403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2224814.
The product of its (nonzero) digits is 120000, while the sum is 38.
Adding to 12525521125403 its reverse (30452112552521), we get a palindrome (42977633677924).
The spelling of 12525521125403 in words is "twelve trillion, five hundred twenty-five billion, five hundred twenty-one million, one hundred twenty-five thousand, four hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.086 sec. • engine limits •