12529433 has 4 divisors (see below), whose sum is σ = 14319360. Its totient is φ = 10739508.

The previous prime is 12529427. The next prime is 12529471. The reversal of 12529433 is 33492521.

12529433 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12529433 - 2¹⁰ = 12528409 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12529396 and 12529405.

It is not an unprimeable number, because it can be changed into a prime (12529403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 894953 + ... + 894966.

It is an arithmetic number, because the mean of its divisors is an integer number (3579840).

Almost surely, 2^12529433 is an apocalyptic number.

It is an amenable number.

12529433 is a deficient number, since it is larger than the sum of its proper divisors (1789927).

12529433 is an equidigital number, since it uses as much as digits as its factorization.

12529433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1789926.

The product of its digits is 6480, while the sum is 29.

The square root of 12529433 is about 3539.6939133208. The cubic root of 12529433 is about 232.2614534101.

The spelling of 12529433 in words is "twelve million, five hundred twenty-nine thousand, four hundred thirty-three".