12530040045041 has 4 divisors (see below), whose sum is σ = 12796636641792. Its totient is φ = 12263443448292.

The previous prime is 12530040045007. The next prime is 12530040045059. The reversal of 12530040045041 is 14054004003521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12530040045041 - 2²⁶ = 12529972936177 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 12530040044995 and 12530040045013.

It is not an unprimeable number, because it can be changed into a prime (12530040045541) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 133298298305 + ... + 133298298398.

It is an arithmetic number, because the mean of its divisors is an integer number (3199159160448).

Almost surely, 2^{12530040045041} is an apocalyptic number.

It is an amenable number.

12530040045041 is a deficient number, since it is larger than the sum of its proper divisors (266596596751).

12530040045041 is an equidigital number, since it uses as much as digits as its factorization.

12530040045041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 266596596750.

The product of its (nonzero) digits is 9600, while the sum is 29.

Adding to 12530040045041 its reverse (14054004003521), we get a palindrome (26584044048562).

The spelling of 12530040045041 in words is "twelve trillion, five hundred thirty billion, forty million, forty-five thousand, forty-one".