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12530512141243 = 71871743496889
BaseRepresentation
bin1011011001010111110010…
…1110011001101110111011
31122100220102221021012010021
42312111330232121232323
53120244442102004433
642352234322231311
72432204525553025
oct266257456315673
948326387235107
1012530512141243
113aa1184485658
1214a45b71b5537
136cb812048bb5
143146a1283015
1516ae325e322d
hexb657cb99bbb

12530512141243 has 4 divisors (see below), whose sum is σ = 12532255645320. Its totient is φ = 12528768637168.

The previous prime is 12530512141187. The next prime is 12530512141253. The reversal of 12530512141243 is 34214121503521.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12530512141243 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12530512141199 and 12530512141208.

It is not an unprimeable number, because it can be changed into a prime (12530512141253) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 871741258 + ... + 871755631.

It is an arithmetic number, because the mean of its divisors is an integer number (3133063911330).

Almost surely, 212530512141243 is an apocalyptic number.

12530512141243 is a deficient number, since it is larger than the sum of its proper divisors (1743504077).

12530512141243 is an equidigital number, since it uses as much as digits as its factorization.

12530512141243 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1743504076.

The product of its (nonzero) digits is 28800, while the sum is 34.

Adding to 12530512141243 its reverse (34214121503521), we get a palindrome (46744633644764).

The spelling of 12530512141243 in words is "twelve trillion, five hundred thirty billion, five hundred twelve million, one hundred forty-one thousand, two hundred forty-three".

Divisors: 1 7187 1743496889 12530512141243