Base | Representation |
---|---|
bin | 1011011001010111110010… |
… | …1110011001101110111011 |
3 | 1122100220102221021012010021 |
4 | 2312111330232121232323 |
5 | 3120244442102004433 |
6 | 42352234322231311 |
7 | 2432204525553025 |
oct | 266257456315673 |
9 | 48326387235107 |
10 | 12530512141243 |
11 | 3aa1184485658 |
12 | 14a45b71b5537 |
13 | 6cb812048bb5 |
14 | 3146a1283015 |
15 | 16ae325e322d |
hex | b657cb99bbb |
12530512141243 has 4 divisors (see below), whose sum is σ = 12532255645320. Its totient is φ = 12528768637168.
The previous prime is 12530512141187. The next prime is 12530512141253. The reversal of 12530512141243 is 34214121503521.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12530512141243 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12530512141199 and 12530512141208.
It is not an unprimeable number, because it can be changed into a prime (12530512141253) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 871741258 + ... + 871755631.
It is an arithmetic number, because the mean of its divisors is an integer number (3133063911330).
Almost surely, 212530512141243 is an apocalyptic number.
12530512141243 is a deficient number, since it is larger than the sum of its proper divisors (1743504077).
12530512141243 is an equidigital number, since it uses as much as digits as its factorization.
12530512141243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1743504076.
The product of its (nonzero) digits is 28800, while the sum is 34.
Adding to 12530512141243 its reverse (34214121503521), we get a palindrome (46744633644764).
The spelling of 12530512141243 in words is "twelve trillion, five hundred thirty billion, five hundred twelve million, one hundred forty-one thousand, two hundred forty-three".
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