Base | Representation |
---|---|
bin | 1011011001011001101000… |
… | …0111000001000110110011 |
3 | 1122100221201021220202222221 |
4 | 2312112122013001012303 |
5 | 3120301444303230420 |
6 | 42352355252541511 |
7 | 2432222663121331 |
oct | 266263207010663 |
9 | 48327637822887 |
10 | 12531005133235 |
11 | 3aa1407795856 |
12 | 14a4714321897 |
13 | 6cb890219234 |
14 | 31470a932b51 |
15 | 16ae60a24caa |
hex | b659a1c11b3 |
12531005133235 has 4 divisors (see below), whose sum is σ = 15037206159888. Its totient is φ = 10024804106584.
The previous prime is 12531005133211. The next prime is 12531005133293. The reversal of 12531005133235 is 53233150013521.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12531005133235 - 25 = 12531005133203 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 12531005133235.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1253100513319 + ... + 1253100513328.
It is an arithmetic number, because the mean of its divisors is an integer number (3759301539972).
Almost surely, 212531005133235 is an apocalyptic number.
12531005133235 is a deficient number, since it is larger than the sum of its proper divisors (2506201026653).
12531005133235 is an equidigital number, since it uses as much as digits as its factorization.
12531005133235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2506201026652.
The product of its (nonzero) digits is 40500, while the sum is 34.
Adding to 12531005133235 its reverse (53233150013521), we get a palindrome (65764155146756).
The spelling of 12531005133235 in words is "twelve trillion, five hundred thirty-one billion, five million, one hundred thirty-three thousand, two hundred thirty-five".
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