Base | Representation |
---|---|
bin | 1011011001011010011010… |
… | …0111101000101010001011 |
3 | 1122100222020220211122101212 |
4 | 2312112212213220222023 |
5 | 3120302412020313233 |
6 | 42352432151203335 |
7 | 2432231122054253 |
oct | 266264647505213 |
9 | 48328226748355 |
10 | 12531215010443 |
11 | 3aa1505204698 |
12 | 14a477267654b |
13 | 6cb8c485122c |
14 | 31472a766963 |
15 | 16ae74180a48 |
hex | b65a69e8a8b |
12531215010443 has 8 divisors (see below), whose sum is σ = 12577834530912. Its totient is φ = 12484605422016.
The previous prime is 12531215010437. The next prime is 12531215010487. The reversal of 12531215010443 is 34401051213521.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12531215010443 - 210 = 12531215009419 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12531215010493) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 49871 + ... + 5006487.
It is an arithmetic number, because the mean of its divisors is an integer number (1572229316364).
Almost surely, 212531215010443 is an apocalyptic number.
12531215010443 is a deficient number, since it is larger than the sum of its proper divisors (46619520469).
12531215010443 is an equidigital number, since it uses as much as digits as its factorization.
12531215010443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4966021.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 12531215010443 its reverse (34401051213521), we get a palindrome (46932266223964).
The spelling of 12531215010443 in words is "twelve trillion, five hundred thirty-one billion, two hundred fifteen million, ten thousand, four hundred forty-three".
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