12531311111234 has 4 divisors (see below), whose sum is σ = 18796966666854. Its totient is φ = 6265655555616.

The previous prime is 12531311111177. The next prime is 12531311111251. The reversal of 12531311111234 is 43211111313521.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 6291082289209 + 6240228822025 = 2508203^2 + 2498045^2 .

It is a junction number, because it is equal to n+sod(n) for n = 12531311111197 and 12531311111206.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3132827777807 + ... + 3132827777810.

Almost surely, 2^{12531311111234} is an apocalyptic number.

12531311111234 is a deficient number, since it is larger than the sum of its proper divisors (6265655555620).

12531311111234 is an equidigital number, since it uses as much as digits as its factorization.

12531311111234 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6265655555619.

The product of its digits is 2160, while the sum is 29.

Adding to 12531311111234 its reverse (43211111313521), we get a palindrome (55742422424755).

The spelling of 12531311111234 in words is "twelve trillion, five hundred thirty-one billion, three hundred eleven million, one hundred eleven thousand, two hundred thirty-four".