Base | Representation |
---|---|
bin | 10111010101110111… |
… | …00011000010010111 |
3 | 1012100100001202010201 |
4 | 23222323203002113 |
5 | 201131020210033 |
6 | 5431251401331 |
7 | 622353153124 |
oct | 135273430227 |
9 | 35310052121 |
10 | 12531413143 |
11 | 5350724197 |
12 | 25188b3247 |
13 | 1249297b82 |
14 | 86c42d74b |
15 | 4d524147d |
hex | 2eaee3097 |
12531413143 has 4 divisors (see below), whose sum is σ = 12837057408. Its totient is φ = 12225768880.
The previous prime is 12531413119. The next prime is 12531413179. The reversal of 12531413143 is 34131413521.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 34131413521 = 683 ⋅49972787.
It is a cyclic number.
It is not a de Polignac number, because 12531413143 - 233 = 3941478551 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12531413113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 152822071 + ... + 152822152.
It is an arithmetic number, because the mean of its divisors is an integer number (3209264352).
Almost surely, 212531413143 is an apocalyptic number.
12531413143 is a deficient number, since it is larger than the sum of its proper divisors (305644265).
12531413143 is an equidigital number, since it uses as much as digits as its factorization.
12531413143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 305644264.
The product of its digits is 4320, while the sum is 28.
Adding to 12531413143 its reverse (34131413521), we get a palindrome (46662826664).
The spelling of 12531413143 in words is "twelve billion, five hundred thirty-one million, four hundred thirteen thousand, one hundred forty-three".
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