Base | Representation |
---|---|
bin | 1011011001011111000101… |
… | …0101110110111110100111 |
3 | 1122101002111021202201012021 |
4 | 2312113301111312332213 |
5 | 3120312443433013303 |
6 | 42353200413004011 |
7 | 2432304153543013 |
oct | 266276125667647 |
9 | 48332437681167 |
10 | 12532468641703 |
11 | 3aa1a9891138a |
12 | 14a4a62483607 |
13 | 6cba644a288a |
14 | 314809057543 |
15 | 16aee9261ebd |
hex | b65f1576fa7 |
12532468641703 has 4 divisors (see below), whose sum is σ = 12554188691920. Its totient is φ = 12510748591488.
The previous prime is 12532468641673. The next prime is 12532468641709. The reversal of 12532468641703 is 30714686423521.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12532468641703 - 217 = 12532468510631 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12532468641709) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10860024243 + ... + 10860025396.
It is an arithmetic number, because the mean of its divisors is an integer number (3138547172980).
Almost surely, 212532468641703 is an apocalyptic number.
12532468641703 is a deficient number, since it is larger than the sum of its proper divisors (21720050217).
12532468641703 is an equidigital number, since it uses as much as digits as its factorization.
12532468641703 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21720050216.
The product of its (nonzero) digits is 5806080, while the sum is 52.
The spelling of 12532468641703 in words is "twelve trillion, five hundred thirty-two billion, four hundred sixty-eight million, six hundred forty-one thousand, seven hundred three".
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