Base | Representation |
---|---|
bin | 111010010111001000… |
… | …1111101100111011111 |
3 | 102222111111110200202211 |
4 | 1310232101331213133 |
5 | 4023134102343401 |
6 | 133324231501251 |
7 | 12024543530512 |
oct | 1645621754737 |
9 | 388444420684 |
10 | 125330512351 |
11 | 49174896a30 |
12 | 20358b27827 |
13 | ba84667ca5 |
14 | 60cd280d79 |
15 | 33d7e46951 |
hex | 1d2e47d9df |
125330512351 has 4 divisors (see below), whose sum is σ = 136724195304. Its totient is φ = 113936829400.
The previous prime is 125330512319. The next prime is 125330512379. The reversal of 125330512351 is 153215033521.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 125330512351 - 25 = 125330512319 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (125330512051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5696841460 + ... + 5696841481.
It is an arithmetic number, because the mean of its divisors is an integer number (34181048826).
Almost surely, 2125330512351 is an apocalyptic number.
125330512351 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
125330512351 is a deficient number, since it is larger than the sum of its proper divisors (11393682953).
125330512351 is a wasteful number, since it uses less digits than its factorization.
125330512351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11393682952.
The product of its (nonzero) digits is 13500, while the sum is 31.
Adding to 125330512351 its reverse (153215033521), we get a palindrome (278545545872).
The spelling of 125330512351 in words is "one hundred twenty-five billion, three hundred thirty million, five hundred twelve thousand, three hundred fifty-one".
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