12533154311341 has 4 divisors (see below), whose sum is σ = 13078074064032. Its totient is φ = 11988234558652.

The previous prime is 12533154311299. The next prime is 12533154311351. The reversal of 12533154311341 is 14311345133521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12533154311341 - 2¹⁷ = 12533154180269 is a prime.

It is a super-2 number, since 2×12533154311341² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12533154311341.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12533154311351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 272459876311 + ... + 272459876356.

It is an arithmetic number, because the mean of its divisors is an integer number (3269518516008).

Almost surely, 2^{12533154311341} is an apocalyptic number.

It is an amenable number.

12533154311341 is a deficient number, since it is larger than the sum of its proper divisors (544919752691).

12533154311341 is an equidigital number, since it uses as much as digits as its factorization.

12533154311341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 544919752690.

The product of its digits is 64800, while the sum is 37.

Adding to 12533154311341 its reverse (14311345133521), we get a palindrome (26844499444862).

The spelling of 12533154311341 in words is "twelve trillion, five hundred thirty-three billion, one hundred fifty-four million, three hundred eleven thousand, three hundred forty-one".