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12533171041 = 19962980759
BaseRepresentation
bin10111010110000100…
…10000001101100001
31012100110101001112001
423223002100031201
5201131442433131
65431353204001
7622404124156
oct135302201541
935313331461
1012533171041
1153517149a6
122519400601
131249762051
1486c76a22d
154d548c261
hex2eb090361

12533171041 has 4 divisors (see below), whose sum is σ = 12596152000. Its totient is φ = 12470190084.

The previous prime is 12533171033. The next prime is 12533171051. The reversal of 12533171041 is 14017133521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12533171041 - 23 = 12533171033 is a prime.

It is a super-2 number, since 2×125331710412 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12533171051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31490181 + ... + 31490578.

It is an arithmetic number, because the mean of its divisors is an integer number (3149038000).

Almost surely, 212533171041 is an apocalyptic number.

It is an amenable number.

12533171041 is a deficient number, since it is larger than the sum of its proper divisors (62980959).

12533171041 is an equidigital number, since it uses as much as digits as its factorization.

12533171041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 62980958.

The product of its (nonzero) digits is 2520, while the sum is 28.

The spelling of 12533171041 in words is "twelve billion, five hundred thirty-three million, one hundred seventy-one thousand, forty-one".

Divisors: 1 199 62980759 12533171041