Base | Representation |
---|---|
bin | 1011011001100010001100… |
… | …1001101010100110111111 |
3 | 1122101011122112012212020220 |
4 | 2312120203021222212333 |
5 | 3120321201400243421 |
6 | 42353415344112423 |
7 | 2432333651556261 |
oct | 266304311524677 |
9 | 48334575185226 |
10 | 12533304306111 |
11 | 3aa23875a1426 |
12 | 14a5056305713 |
13 | 6cbb68661a64 |
14 | 314888027b31 |
15 | 16b0477d13c6 |
hex | b662326a9bf |
12533304306111 has 4 divisors (see below), whose sum is σ = 16711072408152. Its totient is φ = 8355536204072.
The previous prime is 12533304306073. The next prime is 12533304306119. The reversal of 12533304306111 is 11160340333521.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12533304306111 - 211 = 12533304304063 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12533304306119) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2088884051016 + ... + 2088884051021.
It is an arithmetic number, because the mean of its divisors is an integer number (4177768102038).
Almost surely, 212533304306111 is an apocalyptic number.
12533304306111 is a deficient number, since it is larger than the sum of its proper divisors (4177768102041).
12533304306111 is an equidigital number, since it uses as much as digits as its factorization.
12533304306111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4177768102040.
The product of its (nonzero) digits is 19440, while the sum is 33.
Adding to 12533304306111 its reverse (11160340333521), we get a palindrome (23693644639632).
The spelling of 12533304306111 in words is "twelve trillion, five hundred thirty-three billion, three hundred four million, three hundred six thousand, one hundred eleven".
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