1253389141981 has 4 divisors (see below), whose sum is σ = 1253392115292. Its totient is φ = 1253386168672.

The previous prime is 1253389141973. The next prime is 1253389142051. The reversal of 1253389141981 is 1891419833521.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 23749892100 + 1229639249881 = 154110^2 + 1108891^2 .

It is a cyclic number.

It is not a de Polignac number, because 1253389141981 - 2³ = 1253389141973 is a prime.

It is a super-2 number, since 2×1253389141981² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1253383141981) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 723880 + ... + 1740913.

It is an arithmetic number, because the mean of its divisors is an integer number (313348028823).

Almost surely, 2^{1253389141981} is an apocalyptic number.

It is an amenable number.

1253389141981 is a deficient number, since it is larger than the sum of its proper divisors (2973311).

1253389141981 is an equidigital number, since it uses as much as digits as its factorization.

1253389141981 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2973310.

The product of its digits is 1866240, while the sum is 55.

The spelling of 1253389141981 in words is "one trillion, two hundred fifty-three billion, three hundred eighty-nine million, one hundred forty-one thousand, nine hundred eighty-one".