12534240113 has 4 divisors (see below), whose sum is σ = 12534478320. Its totient is φ = 12534001908.

The previous prime is 12534240091. The next prime is 12534240119. The reversal of 12534240113 is 31104243521.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31104243521 = 13 ⋅2392634117.

It is a cyclic number.

It is not a de Polignac number, because 12534240113 - 2⁶ = 12534240049 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12534240119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1403 + ... + 158336.

It is an arithmetic number, because the mean of its divisors is an integer number (3133619580).

Almost surely, 2^12534240113 is an apocalyptic number.

It is an amenable number.

12534240113 is a deficient number, since it is larger than the sum of its proper divisors (238207).

12534240113 is an equidigital number, since it uses as much as digits as its factorization.

12534240113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 238206.

The product of its (nonzero) digits is 2880, while the sum is 26.

Adding to 12534240113 its reverse (31104243521), we get a palindrome (43638483634).

The spelling of 12534240113 in words is "twelve billion, five hundred thirty-four million, two hundred forty thousand, one hundred thirteen".