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1253424405445 = 5358396994751
BaseRepresentation
bin10010001111010101111…
…010101001101111000101
311102211022022011002202121
4102033111322221233011
5131014003121433240
62355452031005541
7156362011441102
oct22172572515705
94384268132677
101253424405445
11443635444693
12182b093698b1
1391274946c34
1444947979aa9
152291000904a
hex123d5ea9bc5

1253424405445 has 8 divisors (see below), whose sum is σ = 1504151470080. Its totient is φ = 1002711402000.

The previous prime is 1253424405407. The next prime is 1253424405461. The reversal of 1253424405445 is 5445044243521.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1253424405445 - 211 = 1253424403397 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3318181 + ... + 3676570.

It is an arithmetic number, because the mean of its divisors is an integer number (188018933760).

Almost surely, 21253424405445 is an apocalyptic number.

It is an amenable number.

1253424405445 is a deficient number, since it is larger than the sum of its proper divisors (250727064635).

1253424405445 is an equidigital number, since it uses as much as digits as its factorization.

1253424405445 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7030595.

The product of its (nonzero) digits is 1536000, while the sum is 43.

Adding to 1253424405445 its reverse (5445044243521), we get a palindrome (6698468648966).

The spelling of 1253424405445 in words is "one trillion, two hundred fifty-three billion, four hundred twenty-four million, four hundred five thousand, four hundred forty-five".

Divisors: 1 5 35839 179195 6994751 34973755 250684881089 1253424405445