12535041550401 has 16 divisors (see below), whose sum is σ = 18573230208000. Its totient is φ = 8355435140304.

The previous prime is 12535041550399. The next prime is 12535041550433. The reversal of 12535041550401 is 10405514053521.

12535041550401 is a `hidden beast` number, since 1 + 2 + 53 + 50 + 4 + 1 + 550 + 4 + 0 + 1 = 666.

It is not a de Polignac number, because 12535041550401 - 2¹ = 12535041550399 is a prime.

It is not an unprimeable number, because it can be changed into a prime (12535041550441) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 34796001 + ... + 35154398.

It is an arithmetic number, because the mean of its divisors is an integer number (1160826888000).

Almost surely, 2^{12535041550401} is an apocalyptic number.

It is an amenable number.

12535041550401 is a deficient number, since it is larger than the sum of its proper divisors (6038188657599).

12535041550401 is an equidigital number, since it uses as much as digits as its factorization.

12535041550401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 69957045 (or 69957039 counting only the distinct ones).

The product of its (nonzero) digits is 60000, while the sum is 36.

The spelling of 12535041550401 in words is "twelve trillion, five hundred thirty-five billion, forty-one million, five hundred fifty thousand, four hundred one".