12535041550441 has 2 divisors, whose sum is σ = 12535041550442. Its totient is φ = 12535041550440.

The previous prime is 12535041550439. The next prime is 12535041550483. The reversal of 12535041550441 is 14405514053521.

12535041550441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10631538444816 + 1903503105625 = 3260604^2 + 1379675^2 .

It is a cyclic number.

It is not a de Polignac number, because 12535041550441 - 2¹ = 12535041550439 is a prime.

Together with 12535041550439, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 12535041550394 and 12535041550403.

It is not a weakly prime, because it can be changed into another prime (12535042550441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6267520775220 + 6267520775221.

It is an arithmetic number, because the mean of its divisors is an integer number (6267520775221).

Almost surely, 2^{12535041550441} is an apocalyptic number.

It is an amenable number.

12535041550441 is a deficient number, since it is larger than the sum of its proper divisors (1).

12535041550441 is an equidigital number, since it uses as much as digits as its factorization.

12535041550441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 240000, while the sum is 40.

The spelling of 12535041550441 in words is "twelve trillion, five hundred thirty-five billion, forty-one million, five hundred fifty thousand, four hundred forty-one".