1253708047 has 4 divisors (see below), whose sum is σ = 1254946680. Its totient is φ = 1252469416.

The previous prime is 1253708039. The next prime is 1253708083. The reversal of 1253708047 is 7408073521.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 7408073521 = 5449 ⋅1359529.

It is a cyclic number.

It is not a de Polignac number, because 1253708047 - 2³ = 1253708039 is a prime.

It is a super-2 number, since 2×1253708047² = 3143567734225108418, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1253707997 and 1253708015.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1253708347) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 617797 + ... + 619822.

It is an arithmetic number, because the mean of its divisors is an integer number (313736670).

Almost surely, 2^1253708047 is an apocalyptic number.

1253708047 is a deficient number, since it is larger than the sum of its proper divisors (1238633).

1253708047 is a wasteful number, since it uses less digits than its factorization.

1253708047 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1238632.

The product of its (nonzero) digits is 47040, while the sum is 37.

The square root of 1253708047 is about 35407.7399306988. The cubic root of 1253708047 is about 1078.2814595107.

The spelling of 1253708047 in words is "one billion, two hundred fifty-three million, seven hundred eight thousand, forty-seven".